InterviewSolution
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InterviewSolution
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A transverse wave propagating on a stretched string of linear density 3 × 10-4 kg m-1 is represented by the equation, y = 0.2 sin (1.5x + 60t)Where x is in metres and t is in seconds. The tension in the string (in newtons) is:(a) 0.24(b) 0.48 (c) 1.20 (d) 1.80 |
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Answer» (a) 0.48 v = \(\sqrt{\frac{T}{m}}\) = \(\frac{ω}{k}\) ⇒ T = (\(\frac{ω}{k}\))2 m = \((\frac{60}{1.5})^2\) x 3 x 10-4 = 0.48 N |
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