InterviewSolution
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InterviewSolution
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A transverse wave travelling in a string produce maximum transverse velocity of `3 m//s` and maximum transverse acceleration `90 m//s^(2)` in a particle. If the velocity of wave in the string is `20 m//s`. Datermine the equation of the wave ? |
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Answer» Correct Answer - Equation of wave in string `y = 0.1 sin (30t +- (3)/(2) x + phi)` [where `phi` is initial phase] Maximum particle velocity `v_(max) = omegaA = 3m//s` Maximum particle accelertion `a_(max) = omega^(2) A = 90m//s^(2)` `a_(max) = v_(max) omega = omega xx 3 = 90 m//s^(2) rArr omega = 30s^(-1) rArr A = (3)/(omega) = (3)/(30) = 0.1 m` `k = (omega)/(v) = (30)/(20) = (3)/(2)` [ where `v` is velocity of wave] Equation of wave in string `y = 0.1 sin (30t+-(3)/(2)xrarr)` where `phi` is initial phase] |
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