A transverse wave travelling on a taut string is represented by: `Y=0.01 sin 2 pi(10t-x)` Y and x are in meters and t in seconds. Then,A. The speed of the wave is `10m//s`.B. closet points on the string which differ in phase by `60^(@)` are `(1//6)m` apartC. maximum particle velocity is `pi//4 m//s`D. the phase of a certain point on the string changes by `120^(@)` in `(1//20)` seconds.

A transverse wave travelling on a taut string is represented by: `Y=0.

1.	A transverse wave travelling on a taut string is represented by: `Y=0.01 sin 2 pi(10t-x)` Y and x are in meters and t in seconds. Then,A. The speed of the wave is `10m//s`.B. closet points on the string which differ in phase by `60^(@)` are `(1//6)m` apartC. maximum particle velocity is `pi//4 m//s`D. the phase of a certain point on the string changes by `120^(@)` in `(1//20)` seconds.
Answer» Correct Answer - a., b. `y=0.01 sin [2pi(10t-x)]` `impliesy=0.01sin[20pit-2pix]` `omega=20pi, K=2pi` Wave velocity :`v=(omega)/(k)=(20pi)/(2pi)=10m//s` `Deltaphi=K Deltax`, given `Deltaphi=60^(@)=(pi)/(3)` `(pi)/(3)=2pi DeltaximpliesDeltax=(1)/(6)m` `v_(p-max)=omegaA=20pixx0.01=(pi)/(5)m//s` `Deltaphi_(t)omegaDeltat=20pixx(1)/(20)=pi` so in time `(1)/(20)s`, phase changes by and not `120^(@)`

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