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A travelling acoustic wave of frequency 500 Hz is moving along the positive x-direction with a velocity of 300 ms^(-1).The phase difference between two points x_(1)and x_2 is 60°. Then the minimum separation between the two points is |
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Answer» 1 mm `Deltaphi = (2pi)/lambda. Deltax` , Here, `Deltaphi = 60^(@) = pi/3`, `V= 300 ms^(-1), v= 500 Hz` `therefore pi/3 = (2pi)/(300//500) xx Deltax (therefore v = v lambda)` `rArr Deltax = 3/(2 xx 5 xx 3) = 1/10 m = 10 cm` |
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