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A travelling wave is described by the equation `y = y_(0) sin ((ft - (x)/lambda))`. The maximum particle velocity is equal to four times the wave velocity ifA. `piy_(0)//4`B. `piy_(0)//2`C. `piy_(0)`D. `2piy_(0)`

Answer» The maximum particle velocity of a `SHM` of amplitude `y_(0)` and frequency `f` is `2pify_(0)`. The wave velocity is `f_(A)`. For `2pify_(0)` to be equal to `4flambda`, `lambda` has to be `piy_(0)//2`
(Here `lambda=a`).


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