1.

A travelling wave is described by the equation `y = y_(0) sin ((ft - (x)/lambda))`. The maximum particle velocity is equal to four times the wave velocity ifA. `lambda=(piy_(0))/(4)`B. `lambda=(piy_(0))/(2)`C. `lambda=piy_(0)`D. `lambda=2pi Y_(0)`

Answer» Correct Answer - b
maximum particle velocity `= 4 `wave velocity
`Aomega=4 flambda`
`y_(0)2pi f=4flambda`
`lambda=(piy_(0))/(2)`


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