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A travelling wave is given by `y=(0.8)/((3x^(2)+24xt+48t^(2)+4))` where `x` and `y` are in metres and `t` is in seconds. Find the velocity in `m//s`. |
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Answer» `y=(0.8)/((3x^(2)+12xt+12t^(2)+4))` `=(0.8)/(3[x^(2)+4xt+(2t)^(2)]+4)` `=(0.8)/([4+3(x+2t)^(2)])` on solving, we get `x+2t=x+vt` `v=2 m//s` Amplitude ua `y_(max):` when `x+2t=0` therefore, `y_(max)=(0.8)/(4)=0.2m` |
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