1.

A travelling wave represented by y = A sin (omega t - kx) is superimposed on another wave represented by y = A sin (omega t + kx). the resultant is :

Answer»

A wave travelling along + x direction
A wave travelling along - x direction
A standing wave having NODES at a = `(n lambda)/(2)`, n = 0, 1, 2 .......
A standing wave having nodes at x = `(n + (1)/(2) ) (lambda)/(2) ` ,n = 0, 1, 2 ......

Solution :Y = A sin `(OMEGA t - kx) + A sin omega t + kx)`
Y = 2A sin `omega t `cos kx standingwave
For nodes cos kx = 0
`(2pi)/(lambda) x = ( 2n + 1) (pi)/(2) `
`THEREFORE "" x = ((2n + 1)lambda)/(4) . N = 0 , 1,2,3.... `
So, correct CHOICE is d.


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