A tree is broken at a height of 5 m from the ground and its top touche

1.	A tree is broken at a height of 5 m from the ground and its top touches the ground at adistance of 12 m from the base of the tree .Find the original height of the tree.
Answer» ANSWER:- The Original Height of the TREE is 18 meters. Explanation:- Given:- A tree has broken from 5 m above the ground (Let us say from point A). Its top touches the ground at a distance of 12 m from its base (Let us say point C). To FIND:- The original height of the tree. Theorem used:- Pythagoras Theorem, $\large \blue{ \longrightarrow \boxed{ \red{ \bf {h}^{2} = <klux>B</klux> {}^{2} + {p}^{2}.}}}$ Where, h is Hypotenuse. b is Base. p is Perpendicular. So Here, h = ?? b = 12 m. p = 5m. Now, By putting the above values in theorem we get:- $\tt\longrightarrow {h}^{2} = {b}^{2} + {p}^{2}. \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \tt\longrightarrow h = \sqrt{ {b}^{2} + {p}^{2} } . \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \tt\longrightarrow h = \sqrt{ (12m) {}^{2} + (5m) {}^{2} } . \\ \\ \tt\longrightarrow h = \sqrt{144 {m}^{2} + 25 {m}^{2} }. \: \: \: \: \\ \\ \tt\longrightarrow h = \sqrt{169m {}^{2} }. \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \tt\longrightarrow h = 13 \: m. \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$ THEREFORE The total height of the tree, = 13m + 5m. = 18m.

A tree is broken at a height of 5 m from the ground and its top touches the ground at adistance of 12 m from the base of the tree .Find the original height of the tree.

Answer»

ANSWER:-

The Original Height of the TREE is 18 meters.

Explanation:-

Given:-

A tree has broken from 5 m above the ground (Let us say from point A).

Its top touches the ground at a distance of 12 m from its base (Let us say point C).

To FIND:-

The original height of the tree.

Theorem used:-

Pythagoras Theorem,

$\large \blue{ \longrightarrow \boxed{ \red{ \bf {h}^{2} = <klux>B</klux> {}^{2} + {p}^{2}.}}}$

Where,

h is Hypotenuse.

b is Base.

p is Perpendicular.

So Here,

h = ??

b = 12 m.

p = 5m.

Now,

By putting the above values in theorem we get:-

$\tt\longrightarrow {h}^{2} = {b}^{2} + {p}^{2}. \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \tt\longrightarrow h = \sqrt{ {b}^{2} + {p}^{2} } . \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \tt\longrightarrow h = \sqrt{ (12m) {}^{2} + (5m) {}^{2} } . \\ \\ \tt\longrightarrow h = \sqrt{144 {m}^{2} + 25 {m}^{2} }. \: \: \: \: \\ \\ \tt\longrightarrow h = \sqrt{169m {}^{2} }. \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \tt\longrightarrow h = 13 \: m. \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

THEREFORE The total height of the tree,

= 13m + 5m.

= 18m.