A triangular park ABC has sides 120m , 80m, 50m A gardener has to put a fence all around it and also plant grass inside how much area does he need to plant find the cost of fencing wire at the rate of 2 rupees per meter leaving a space of 3m width for a gate on one side

A triangular park ABC has sides 120m , 80m, 50m A gardener has to put

1.	A triangular park ABC has sides 120m , 80m, 50m A gardener has to put a fence all around it and also plant grass inside how much area does he need to plant find the cost of fencing wire at the rate of 2 rupees per meter leaving a space of 3m width for a gate on one side
Answer» 50+80+120=250mThen,\bold{SEMIPERIMETER}Semiperimeter \large{ \frac{250}{2} = 125m}2250=125m• s - a \:( 125-120 ) = 5ms−a(125−120)=5m• s - a \:( 125-80 ) = 45ms−a(125−80)=45m• s - a \:( 125-50 ) = 75ms−a(125−50)=75m\begin{lgathered}Area = \SQRT{125(5)(45)(75)} \\ \: \: \: \: \: \: \: \: \: \: = 375 \sqrt{{15}m^{2} }\end{lgathered}Area=125(5)(45)(75)=37515m2\begin{lgathered}Now, \: perimeter = 250 - 3m \: (gate) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 247m\end{lgathered}Now,perimeter=250−3m(gate)=247mCost \: = 20 \times 247Cost=20×247\large{\fbox{\bold{\red{= 4,940}}}}=4,940