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A triangular sail has a perimeter of 25 m. Side a is 2 m shorter than twice side b, and side c is 3 m longer than side b. Find the length of each side. |
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Answer» Perimeter of triangular sail = 25 mSide 'a' is 2m shorter than twice of SIDE 'b'Side 'c' is 3m LONGER than side 'b'To FIND :Length of each sideFormula used :Perimeter of triangle = Sum of all sideSolution :Let - Side b = x mTherefore, side a = 2b - 2side a = (2x - 2)mSide c = 3m + x mside c = (3+ x) mNow perimeter of triangular sail = side a + side b + side cPerimeter of triangular sail = (2x-2) + (x) + (3+x)Perimeter of triangular sail = 2x - 2 + x + 3 + xPerimeter of triangular sail = 4x + 1NOW according to question, Perimeter of triangular sail = 25mTherefore, 4x + 1 = 254x = 25 - 14x = 24x = 24 ÷ 4x = 6Therefore ,1) side b = x = 6m2) side a = (2x-2) mside a = 2(6) - 2 mside a = 12 - 2 mside a = 10m3) side c = 3 + xside c = 3 + 6mside c = 9 mANSWER :Side a = 10 mSide b = 6 mSide c = 9 m |
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