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A triode has a plate resistance of 10 k Omega and amplification factor 24. If the input signal voltage is 0.4 V(r.m.s), and the load resistance is 10 k ohm, then, the output voltage is (r.m.s.) is |
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Answer» `4.8 V` Now `A=(24xx10k)/(10k+10k)=(24xx10)/20=12` THEREFORE, `V_(0)=12xx0.4=4.8` volt (r.m.s.) |
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