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A triple stars system consists of two stars each of mass m in the same circular orbit about central star with mass `M=2xx10^(33)kg`. The two outer stars always lie at opposite ends of a diameter of their common circular orbit the radius of the circular orbit is `r=10^(11)` m and the orbital period each star is `1.6xx10^(7)s` [take `pi^(2)=10` and `G=(20)/(3)xx10^(-11)Mn^(2)kg^(-2)`] Q. The orbital velocity of each star isA. `5/4sqrt(10) xx10^(3) m//s`B. `5/4sqrt(10) xx10^(5) m//s`C. `5/4sqrt(10)xx10^(2) m//s`D. `5/4 sqrt(10)xx10^(4) m//s` |
Answer» Correct Answer - D `T=(2pir)/vrArr v=(2pir)/T=((2)(sqrt(10))(10^(11)))/(1.6xx10^(7))` `=5/4sqrt(10)xx10^(4)ms^(-1)`. |
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