1.

A tritrium gas target is bombared with a beam of monoenergetic protons of kineticenergy K_(1) =3 MeV The KE of the neutron emiited at 30^(@) to the inicdent beam is K_(2) ? Find the value of K_(1)//K_(2) (approximately in whole number). Atomic masses are H^(1) =1.007276 amu, n^(1)=1.008665 amu, ._1 H^3=3.016050 amu, ._2He^3=3.016030 amu.

Answer»


Solution :Nuclear reaction is `._(1)H^(1) +._(1)H^(3) RARR ._(2)He^(3) +_(0)n^(1)+Q`
`Q=-1.2745 MEV`
Using CONSERVATION of linear momnetum, we get
`K_(2) =1.44 MeV, K_(1) =3 MeV` .


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