1.

A truck accelerates from speed v to 2 v. Work done in during this is

Answer»

 three times as the work done in accelerating it from REST to v.
same as the work done in accelerating it from rest to v
four times as the work done in accelerating it from rest to v.
less than the work done in accelerating it from rest tov.

Solution :Work done = INCREASE in K.E.
`:.(W_1)/(W_2)=(1/2m((2v)^2-v^2))/(1/2m(v^2-0))`
=`(4v^2-v^2)/(v^2)=3`
So`W_1=3W_2`


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