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A truck of mass 1000 kg accelerates uniformly from rest to a velocity of 15 ms-1 in 5 seconds. Calculate (i) its acceleration, (ii) its gain in K.E., (iii) average power of the engine during this period, neglect friction. |
Answer» (i) \(a = \frac{v-u}{t}\) = 3m/s2 (ii) Gain in K.E. = \(\frac{1}{2}\)m(v2- u2) = 1.125 x 105 J (iii) P = \(\frac{W}{t}\) = 22500W. |
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