1.

A truck of mass 1000 kg accelerates uniformly from rest to a velocity of 15 ms-1 in 5 seconds. Calculate (i) its acceleration, (ii) its gain in K.E., (iii) average power of the engine during this period, neglect friction.

Answer»

(i) \(a = \frac{v-u}{t}\) = 3m/s2

(ii) Gain in K.E. = \(\frac{1}{2}\)m(v2- u2) = 1.125 x 105 J

(iii) P = \(\frac{W}{t}\) = 22500W.



Discussion

No Comment Found

Related InterviewSolutions