1.

A tube of length h (which is wide enough so that surface tension effects can be neglected) filled with air at atmosphere pressure and closed at one end. Now tube is lowered in a tank of mercury to a depth h as shown. It is seen that mercury rises a distance x into the tube. If the mercury barometer also reads h, then

Answer»

<P>`h(h-x)=h^(2)`
`(2H-x)(h-x)=h^(2)`
`(2h-x)(h+x)=h^(2)`
`(2h)(h-x)=h^(2)`

Solution :For air in tube, `P_(0)ha=P(h-x)aimpliesP'=(P_(0)h)/(h-x)=(h^(2)deltag)/(h-x)""("Given":P_(0)=hdeltag)`
At BOTTOM most POINT, `P_(0)+deltagh=P'+deltagximplies2deltagh=(deltagh^(2))/(h-x)+deltagximplies(2h-x)(h-x)=h^(2)`


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