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A tube of length L is filled completely with an incompressible liquid of mass M and closed at both the ends. The tube is then rotated in a horizontal plane about one of its ends with a uniform angular velocity omega. The force exerted by the liquid at the other end is |
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Answer» `(Momega^(2)L)/2` `therefore` Mass in eIement dx=`(Mdx)/L` `therefore` Centripetal force =`((Mdx)/L)xomega^(2)` or `dF=(Momega^(2))/Lxdx` `thereforeintdF=int_(0)^(L)(Momega^(2))/Lxdx` or `F=(Momega^(2))/L[(x^(2))/2]_(0)^(L)=(ML^(2)omega^(2))/(2L)` or `F=(MLomega^(2))/2` 
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