1.

A tube with thin but uniform cross section has two arms, one straight, othe shaped as a semicircle of radius r. Initially both arms carry an ideal fluid upto a height R. Now the equilibrium is disturbed by pushing the fluid in the left arm by a small amount. Fluid is the released and allowed oscillate. Neglect any friction or viscous forces. If the period of oscillations is found to be T=pisqrt((nR)/(3g)(pi+n)), find the integer value n

Answer»


SOLUTION :`-Arhogxx(1+sin30^(@))=ArhoR[(pi)/2+cosec30^(@)](d^(2)x)/(dt^(2))`
`implies(d^(2)x)/(dt^(2))=-((GX)/R)((3//2)/((pi)/2+2))`
`implies T=pi sqrt((4R(pi+4))/(3g))`


Discussion

No Comment Found

Related InterviewSolutions