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A tuning fork gives 5 beat/second with another fork of 500hz .when the fork is loaded then the frequency of the ist fork. |
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Answer» Solution :`n_1 = n_2 +- 5 = 500 +-5 =` 505Hz or 495Hz when `n_1` is LOADED its FREQUENCY decreases and given that beat frequency remains unchanged. This is POSSIBLE only when `n_1` = 505Hz. |
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