1.

A tuning fork produces 4 beats/sec. with another fork of frequency 288 cps. A little wax is placed on the unknown fork and it then produces 2 beats/sec. the unknown frequency is :

Answer»

286 cps
284 cps
292 cps
290 cps

Solution :Unknown frequency `v_(2) = v_(1) PM b = 288 pm 4 = 292 or 284 `Hz.
since on loading no. Of beats decreases.
`THEREFORE v_(2) = 292 ` Hz.
CORRECT choice is (c).


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