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A tuning is dug along the diameter of the earth. There is particle of mass `m` at the centre of the tunel. Find the minimum velocity given to the particle so that is just reaches to the surface of the earth. `(R =` radius of earth)A. `sqrt((GM)/(R))`B. `sqrt((GM)/(2R))`C. `sqrt((2GM)/(R))`D. it will reach with the help of negligible velocity |
Answer» Correct Answer - A `K_(i) + U_(i) = K_(f) + U_(f)` `:. (1)/(2) m nu^(2) - (3)/(2) (GMm)/(R ) = 0 - (GMm)/(R )` Solving, we get `nu = sqrt((GM)/(R ))` |
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