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A tuningfork 'A' produces 6 beats per second with another fork 'B'. On loading 'B' with a little wax, it produces 5 beats per second with 'A'. If the frequency of 'A'is 256 Hz find the frequency of 'B?. |
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Answer» Solution :Let the FREQUENCIES of the forks be `n_(A) and n_(B)` RESPECTIVELY. They produce 6 beat, per second. `:.n_(A)=n_(B)=6 or n_(B)-n_(A)=6` The frequency of .B. decreases on loading i.e. `n_(B) lt n_(B)` The beat frequency after loading is 5. `:.n_(A)-n_(B)=5 or :. n_(B)-n_(A)=5` If originally `n_(A)-n_(B)=6` is correct, then `n_(A)-n_(B) gt 6` But it is not so. The beat frequency did not increase `:.` Originally `n_(B)-n_(A)=6` is correct `n_(B)=n_(A)+6256+6=262 HZ` |
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