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A tunning fork of frequency 500 Hz is sounded on a resonance tube. The first & second resonances are obtained at 17 cm and 52 cm. The velocity of sound in m/s : |
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Answer» 170 Now `l_(2) - l_(1) = LAMBDA//2"" rArr lambda = 2 (52 - 17) = 70 ` cm Now v = v `lambda = 500 xx 0.7 = 350MS^(-1)`. hence correct choice is (b) . |
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