1.

A tunning fork of frequency 500 Hz is sounded on a resonance tube. The first & second resonances are obtained at 17 cm and 52 cm. The velocity of sound in m/s :

Answer»

170
350
520
850

Solution :v = 500 Hz, `l_(1) = 17 cm , l_(2) = 52 ` cm.
Now `l_(2) - l_(1) = LAMBDA//2"" rArr lambda = 2 (52 - 17) = 70 ` cm Now v = v `lambda = 500 xx 0.7 = 350MS^(-1)`.
hence correct choice is (b) .


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