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A turn of radius 600 m is banked for a vehicle of mass 200 kg going with a speed of `180kmh^(-1)` . Determine the banking angle of its path. |
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Answer» The turn is banked for speed, `v=180"kmh"^(-1)=180xx(5)/(18)"ms"^(-1)=50ms^(-1)` and radius r = 600m `because" "tantheta=(v^(2))/(rg)=(50xx50)/(600xx10)` `rArr" "tantheta=(25)/(60)=0.417` `rArr" Banking angle "theta=tan^(-1)(0.417)` `rArr" "theta=22.6^(@)` |
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