1.

A turn of radius 600 m is banked for a vehicle of mass 200 kg going with a speed of `180kmh^(-1)` . Determine the banking angle of its path.

Answer» The turn is banked for speed,
`v=180"kmh"^(-1)=180xx(5)/(18)"ms"^(-1)=50ms^(-1)`
and radius r = 600m
`because" "tantheta=(v^(2))/(rg)=(50xx50)/(600xx10)`
`rArr" "tantheta=(25)/(60)=0.417`
`rArr" Banking angle "theta=tan^(-1)(0.417)`
`rArr" "theta=22.6^(@)`


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