1.

A TV tower has a height of 100 m. What is the maximum distance upto which the TV transmission can be received? R=8xx10^(6)m

Answer»

34.77 KM
32.70 km
40km
 40.70 km

Solution :`d=sqrt(2HR)=2xx100xx8xx10^(6)`=40.000 m= 40 km


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