1.

A TV tower has a height of 110 m. How much population is covered by the TV broadcast of the average population density around the tower is 1000 km^-2? Given that radius of earth=6.4xx10^6m.

Answer»

SOLUTION :RADIUS of the AREA covered by TV broadcast is `d = SQRT(2Rh)`
Here, `R=6.4xx10^6m,h=110m`
`d=sqrt(2xx6.4xx10^6xx110)=37500m=37.5km`
POPULATION covered = `Population densityxxpid^2=1000xxpi37.5)^2=4.4xx10^6`


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