A two- digit number is 1 more than 5 times the sum of its digits.If 9

1.	A two- digit number is 1 more than 5 times the sum of its digits.If 9 is added to the number, its digits are reversed. Find the number.please answer my question step by step.
Answer» Answer: LET the FIRST digit be x And second digit be y - According to question $\implies$ 10x + y = 5(x+y) $\implies$ 10x + y = 5x + 5y Therefore, x = 4/5y. ......(1) Now, $\implies$ 10y + x + 9 = 10x + 9y $\implies$ 9y - 9x = 9 y - x = 1. .......(2) PUTTING VALUE of x from (1) in (2) , we get $\implies$ y - 4/5y = 1 $\implies$ 5y - 4y = 5 $\boxed{y = 5}$ ☆ Therefore x = 4/5 . 5 $\bigstar \large \red{x = 4}$ $\text{[math]}$ Mark me as BRAINLIEST

A two- digit number is 1 more than 5 times the sum of its digits.If 9 is added to the number, its digits are reversed. Find the number.please answer my question step by step.

Answer»

Answer:

LET the FIRST digit be x

And second digit be y

- According to question

$\implies$ 10x + y = 5(x+y)

$\implies$ 10x + y = 5x + 5y

Therefore,

x = 4/5y. ......(1)

Now,

$\implies$ 10y + x + 9 = 10x + 9y

$\implies$ 9y - 9x = 9

y - x = 1. .......(2)

PUTTING VALUE of x from (1) in (2) , we get

$\implies$ y - 4/5y = 1

$\implies$ 5y - 4y = 5

$\boxed{y = 5}$

☆ Therefore

x = 4/5 . 5

$\bigstar \large \red{x = 4}$

$\text{[math]}$ Mark me as BRAINLIEST

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A two- digit number is 1 more than 5 times the sum of its digits.If 9 is added to the number, its digits are reversed. Find the number.please answer my question step by step.​