1.

A two-digit number is 7 times the sum of its digits. The number formed byreversing the digits is 18 less than the original number. Find the number. ​

Answer»

let the digits be x and y.... so NUMBER is 10x + y

so as GIVEN in QUES. , 10x+y = 7(x+y)

3x - 6y = 0

x-2y =0...... eq1

now reversed number is 10y + x

so, 10y+x = 10x+y-18

-9x +9y = -18

x-y = 2....... eq2

eq1 - eq2

y= 2

x = 4

so number is 42



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