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A Two-digit Number Is Seven Times The Sum Of Its Digits, If Each Digit Is Increased By 2, The Number Thus Obtained Is 4 More Than Six Times The Sum Of Its Digits, Find The Number ? |
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Answer» LET the two-digit number be 10x + y 10x + y = 7(X + y) ? x = 2y ...(i) 10(x +2 ) + (y + 2) = 6(x + y + 4) + 4 or 10x + y + 22 = 6X + 6y + 28 ? 4x - 5y = 6 ...(ii) Solving equations (i) and (ii) We GET x = 4 and y = 2. Let the two-digit number be 10x + y 10x + y = 7(x + y) ? x = 2y ...(i) 10(x +2 ) + (y + 2) = 6(x + y + 4) + 4 or 10x + y + 22 = 6x + 6y + 28 ? 4x - 5y = 6 ...(ii) Solving equations (i) and (ii) We get x = 4 and y = 2. |
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