A Two Digit Number Is Such That The Product Of The Digits Is 6. When

1.	A Two Digit Number Is Such That The Product Of The Digits Is 6. When 45 Is Added To The Number, Then The Digits Are Reversed. The Number Is:
Answer» Let the ten's and unit digit be X and 8/x respectively. Then, 10x + 6/x + 45 = 10 x 6/x + x => 10x2 + 6 + 45x = 60 + x2 => 9X2 + 45x 54 = 0 => x2 + 5X 6 = 0 => (x + 6)(x 1) = 0 => x = 1 So the number is 16 Let the ten's and unit digit be x and 8/x respectively. Then, 10x + 6/x + 45 = 10 x 6/x + x => 10x2 + 6 + 45x = 60 + x2 => 9x2 + 45x 54 = 0 => x2 + 5x 6 = 0 => (x + 6)(x 1) = 0 => x = 1 So the number is 16

A Two Digit Number Is Such That The Product Of The Digits Is 6. When 45 Is Added To The Number, Then The Digits Are Reversed. The Number Is:

Answer»

Let the ten's and unit digit be X and 8/x respectively.

Then, 10x + 6/x + 45 = 10 x 6/x + x

=> 10x2 + 6 + 45x = 60 + x2

=> 9X2 + 45x 54

= 0

=> x2 + 5X 6

= 0

=> (x + 6)(x 1)

= 0

=> x = 1

So the number is 16

Let the ten's and unit digit be x and 8/x respectively.

Then, 10x + 6/x + 45 = 10 x 6/x + x

=> 10x2 + 6 + 45x = 60 + x2

=> 9x2 + 45x 54

= 0

=> x2 + 5x 6

= 0

=> (x + 6)(x 1)

= 0

=> x = 1

So the number is 16