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(a). Two electrolytic cells containing silver nitrate solution and dilute sulphuric acid solution were connected in series. A steady current of 2.5 amp was passed through them till 1.078g of silver was deposited (Ag=107.8" g "mol^(-1),1F=96500C] (i) How much electricity was consumed? (ii) What was the weight of oxygen gas liberated?

Answer»


Solution :(i) `Ag^(+)+etoAg, 1 mol (107.8g)` are deposited by 1F `therefore1.078` will be deposited by 0.01 F=965C
(ii) `2H_(2)Oto4H^(+)+O_(2)+4E^(-)` on each electrode
4F LIBERATED 32g `O_(2) therefore0.01F` will liberate `O_(2)=0.08g`
`O_(2)` liberated on both electrodes=`=2xx0.08g=0.16`G.


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