InterviewSolution
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InterviewSolution
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(a) Two masses one n times heavier than the other are dropped from same height. How do their momentum compare just before they hit the ground ? (b) Two masses one n times heavy as the other heave equal knetic energy. How do their momentum compare ? |
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Answer» (a) When dropped from same height, the two masses hit the ground with same velocity `=sqrt(2gh)` `:. (P_(2))/(P_(1))=(m_(2))/(m_(1))=n` (b) We know that K.E., `K=(p^(2))/(2m)` `:. P=sqrt(2mK)` As K is same, `(p_(2))/(p_(1))=sqrt((m_(2))/(m_(1)))=sqrt(n)` |
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