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A tyre pumped to a pressure of 3 atmospheresuddenly bursts. Calculate the fall in temperaturedue to adiabatic expansion. The temperature ofair before expansion is 27°C and value ofAns. 80.8°c]

Answer»

PV^gamma = constant.PV =nRT,P*(nRT/P)^gamma = constant.(P^1-gamma)*(T)^gamma = constant.T=300 K and P = 3 atmfor P= 1 atm as initial and final pressure of tyre is the same!Get TT =219.19 K so dt=80.2 or C.



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