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A uniform chain of length 2 m is kept on a table such that a length of 60 cm hangs freely from the edge of the table. The total mass of the chain is 4 kg. What is the work done in pulling the entire chain on the table ? |
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Answer» 7.2 J Length hanging verticallly =`(60)/(100)=0.6 m` The w.t of hanging part is acting at C.G. of this part i.e at a distance =`(0.6)/(2)=0.3m` from FREE end. Mass of hanging part `=(4/2xx0.6)=1.2kg`. `:.` Work done =`1.2xx10xx0.3` (`:.` Work done = change in P.E. MGH) |
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