A uniform chain of length L and mass m is lying on a smooth table. One third of its length is hanging verti cally down over the edge of the table. How much work need to be done to pull the hanging part back to the table ?

A uniform chain of length L and mass m is lying on a smooth table. One

1.	A uniform chain of length L and mass m is lying on a smooth table. One third of its length is hanging verti cally down over the edge of the table. How much work need to be done to pull the hanging part back to the table ?
Answer» `(MGL)/(3)` `(Mgl)/(9)` `(Mgl)/(8)` Mgl Solution :Work done,`W=(MgL)/(2n^(2))=(MgL)/(2XX2^(2))=(MgL)/(8)`

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A uniform chain of length L and mass m is lying on a smooth table. One third of its length is hanging verti cally down over the edge of the table. How much work need to be done to pull the hanging part back to the table ?

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