Saved Bookmarks
| 1. |
A uniform constant magnetic field B is directed at an angle of 45^@ to the x-axis in xy-plane. PQRS is a rigid square wire frame carrying a steady current i with its centre at the origin O. At time t=0, the frame is at rest in the position shown in the figure, with its side parallel to x and y axis. Each side of the frame is of mass M and length L. (a) What is the torque vec tau about O acting on the frame due to magnetic field? (b) Find the angle by which the frame rotates under the action of this torque in a short interval of time Delta t, and the axis about which this rotation occurs (Delta t is so short that any variation in the torque during this interval may be neglected). |
|
Answer» Solution :` tau= (i_0L^2B)/(SQRT(2))(- hat i + hatj)` `(B) 3/4 (i_0B)/(M)(DELTAT)^2` |
|