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A uniform cylider of mass `M` and radius R has a string wrapped around it. The string is held fixed and the cylinder falls vertically, as in figure. (a). Show that the acceleration of the cylinder is downward with magnitude `a=(2g)/(3)` (b). Find the tension in the string. |
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Answer» `a=(Mg-T)/(M)` ..(i) `alpha=(TR)/((1)/(2)MR^(2))=(2T)/(MR)` ..(ii) `a=Ralpha` Solving these three equation we get `a=(2g)/(3)` and `T=(Mg)/(3)` |
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