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A uniform cylinder has radius `R` and length `L`. If the moment of inertia of this cylinder about an axis passing through its centre and normal to its circular face is `mg` equal to the moment of inertia of the same cylinder about an axis passing through its centre and normal to its length, then |
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Answer» Moment of inertia of cylinder about an axis passing through centre and normal circular face `=(MR^(2))/2` Moment of inertia of cylinder about an axis passing through centre and its length `=M[(L^(2))/12+(R^(2))/4]` But `(MR^(2))/2=M[(L^(2))/12+(R^(2))/4]` `(R^(2))/2=(L^(2))/12+(R^(2))/4rArr(R^(4))/4=(L^(2))/12,` `:. L=sqrt(3)R` |
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