1.

A uniform cylinder of length L and mass M having crosssectional area A is suspended, with its length vertical, from a fixed point by a massless spring, such that it is half submerged in a liquid of density sigma at equilibrium position. The extension x_(0) of the spring when it is in equilibrium is :

Answer»

`(Mg)/k(1-(Lasigma)/M)`
`(Mg)/k(1-(LAsigma)/(2M))`
`(Mg)/k(1+(LAsigma)/M)`
`(Mg)/k`

SOLUTION :At equilibrium `sumF = 0`
`kx_(0)+((AL)/2sigmag)-Mg=0`
`x_(0)=Mg[1-(Lasigma)/(2M)]`
So, CORRECT choice is (b).


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