1.

A uniform disc of mass m and radius r rotates about frictionless axle passing through its centre and perpendicular to its plane. A chord is wound over the rim of the disc. A uniform force F is applied to the other end of chord. The tangential acceleration is proportional to :

Answer»

`R^(1)`
`R^(-1)`
`R^(-2)`
`R^(0)`

Solution :Here `I.alpha=Fr`
`alpha=(Fr)/((1)/(2)Mr^(2))=(2F)/(r.M)`
`r.alpha=a=(2F)/(M)` = CONSTANT.


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