A uniform electric field of 1 MV/m and a unifordi magnetic field of 10^(-2) T were set up in some region of space. The electric field strength vector is perpendicular to the magnetic induction vector. A muon beam moves in a direction perpendicular to both vectors and passes without being deflected by the combined action of both fields. What is the velocity of the particles? Can the charge of the particle and its sign be determined in this experiment?

A uniform electric field of 1 MV/m and a unifordi magnetic field of 10

1.	A uniform electric field of 1 MV/m and a unifordi magnetic field of 10^(-2) T were set up in some region of space. The electric field strength vector is perpendicular to the magnetic induction vector. A muon beam moves in a direction perpendicular to both vectors and passes without being deflected by the combined action of both fields. What is the velocity of the particles? Can the charge of the particle and its sign be determined in this experiment?
Answer» Solution :The condition for the balance of forces is e eE EUB from which ve get u= E/B. Since the CHANGE in the sign of the particle.s CHARGE is accompanied by a simultaneous REVERSAL in the direction of both the electric and the magnetic forces, the sign of the charge cannot be established.

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