InterviewSolution
Saved Bookmarks
| 1. |
A uniform force of `(3hati+hatj)` N acts on a particle of mass 2kg. Hence, the particle is displaced from position `(2hati+hatk)`m to position `(4hati+3hatj-hatk)`m. The work done by the force on the particle isA. 9 JB. 6 JC. 13 JD. 15 J |
|
Answer» Correct Answer - A Displacement `=vecr_(2)-vecr_(1)=(4hati+3hatj-hatk)-(2hati+hatk)` `=2hati + 3 hatj- 2 hatk ` Force `vecF=3hati+hatj` Work `W=vecF.vecd=(3hati+hatj).(2hati+3hatj-2hatk)` `=6+3=9J` |
|