1.

A uniform force of `(3hati+hatj)` N acts on a particle of mass 2kg. Hence, the particle is displaced from position `(2hati+hatk)`m to position `(4hati+3hatj-hatk)`m. The work done by the force on the particle isA. 9 JB. 6 JC. 13 JD. 15 J

Answer» Correct Answer - A
Displacement `=vecr_(2)-vecr_(1)=(4hati+3hatj-hatk)-(2hati+hatk)`
`=2hati + 3 hatj- 2 hatk `
Force `vecF=3hati+hatj`
Work `W=vecF.vecd=(3hati+hatj).(2hati+3hatj-2hatk)`
`=6+3=9J`


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