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A uniform ring of mass m is placed on a rough horizontal fixed surface as shown in the figure. The coefficient of friction between the left part of the ring and left part of the horizontal surface is mu_(1)=0.6pi and between right half and the surface is mu_(2)=0.2pi. At the instant shown, now the ring has been imparted an angular velocity in clockwise sense in the figure shown. At this moment magnitude of acceleration of centre O of the ring (in m//s^(2)) is (take g=10m//s^(2)) |
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Answer» `:.a=(2(mu_(1)-mu_(2))Rlamdag)/(2piRlamda)=4` 
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