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A uniform rod of length l is placed with one end in contact with the horizontal and is then inclined at an angle a to the horizontal and allowed to fall, without slipping at contact point. When it becomes horizontal, its angular velocity will be |
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Answer» `omega=sqrt((3gsinalpha)/l)` P.E. of rod= MG`.l/2sinalpha` Rotational K.E. =`1/2Iomega^(2)=1/2(ML^(2))/3omega^(2)` `mgl/2sinalpha=1/2.(ml^(2))/3.omega^(2)rArromega=sqrt((3gsinalpha)/l)` |
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