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A uniform rod of mass `m` and length is acted upon by the forces `F_(1)` and `F_(2)` Find that: a. linear-and angular acceleration of the rod. b. value of `x` for which the point `P` does not accelerate. |
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Answer» a. Equation of motion `F_(1)+F_(2)=ma` or `2F-F=maimpliesa=(3F)/m`…….i torque equation about centre of mass. `2F.l/2-F.x=((ml^(2))/12)alpha` `implies alpha(12F(l-x))/(ml^(2))` ………ii b. If point `P` does not acceleration `veca_(P)=veca_(P,C)+veca_(C)` As `a_(P)=0=-ax+aimpliesax=a` `(12F(l-x))/(ml^(2))=(3F)/m` which given `x=l/2` |
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