InterviewSolution
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InterviewSolution
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A uniform rod of mass `m` and length `l` is applied pivoted at point `O`. The rod is initially in vertical position and touching a block of mass `M` which is at rest on a horizontal surface. The rod is given a slight jerk and it starts rotating about point `O` this causes the block to move forward as shown The rod loses contact with the block at `theta=30^(@)` all surfaces are smooth now answer the following questions. Q. The hinge reaction at `O` on the rod when it loses contact with the block isA. `(3mg)/(4)(hati+hatj)`B. `((mg)/(4))hatj`C. `((mg)/(4))hati`D. `(mg)/(4)(hati+hatj)` |
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Answer» `a_(C)=((3sqrt(3))/(8)cos60^(@)-(3)/(8)gcos30^(@))hati` `+((3sqrt(3)g)/(8)gcos30^(@)+(3)/(8)gcos60^(@))(-hatj)` `=-((3g)/(4))hatj` Now, `mg(-hatj)+F_("hinge")=ma_(C)` substituting the value we get `F_("Hinge")=((mg)/(4))hatj` |
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