1.

A uniform rod of mass M and lengthL is suspended in vertical position as shown in figure. A uniform horizontal electric field of strength E is present in the region. The rod undergoes small oscillation for different cases. Select correct statement (s)

Answer»

if a POINT CHANGE `Q` is placed at the centre of mass of rod the TIME period becomes
`2pisqrt((2L)/(3[g^(2)+((QE)/(M))^(2)]^(1//2)))`
the time period for small oscillation of rod is if rod is uncharged is `2pisqrt((2L)/(3g))`
if the point charge Q is place a the lower edge of the rod the time period becomes `2pisqrt((2L)/(3[g^(2)+((QE)/(M))^(2)]^(1//2)))`
if the charge Q is uniformly distributed over the rod the time period
becomes `2pisqrt((2L)/(3[g^(2)+((QE)/(M))^(2)]^(1//2)))`

Solution :
(a). `T=2pisqrt((T)/(Mgd))=sqrt((2L)/(3g))`
(b). `g_(eff)=sqrt(g^(2)+((QE)/(M))^(2)),T=sqrt((I)/(MG_(eff)d))`


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