1.

A uniform rope of their mass density lamda and length l is coiled on smooth horizontal surface. One end is pulled up by an external agent wit consant vertical velocity v. Choose the correct option(s)

Answer»

<P>Power developed by external agent as a function of `X` is `P=lamdaxgv`
Power developed by external agent as a function of `x` is `P=(lamdav^(2)+lamdaxg)v`
ENERGY lost during the complete lift of the rope is zero
Energy lost during the complete lift of the rope is `(lamdalv^(2))/2`

Solution :`F` APPLIED by external agent `=` Weight `+` thrust force `=lamdaxg+lamdav^(2)`
Energy lost in the complete lift `=W_(F)-DeltaK.E. -DeltaU=(lamda lv^(2))/2`


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