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A uniform solid sphere of relative density 5 is released in water filled in a long vertical tube. Its terminal velocity achived is `V`. If another uniform solid sphere of same material but double the radius is released in the same water then the terminal velocity achived will be.A. `V`B. `4V`C. `(V)/(4)`D. `2V` |
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Answer» Correct Answer - B Initially the terminal velocity `V` of sphere of radius `a` is `W_(eff)=6pietaaV` (1)`(W_(eff)=`weight`-`Buoyant force) As the radius is doubled, mass is increased to 8 times and new terminal velocity will be `8W_(eff)=6pieta2aV^(`)` .(2) From (1) and (2) `V^(`)=4V` |
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